document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=810649>Question 810649</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A farmer has 3000 feet of wire to enclose a rectangular field. He plans to fence the entire area and hen subdivide it by running a fence across the middle. Find the dimensions of the field that would enclose the maximum area . What is the maximum area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488320 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rectangle dimensions would be like, x and y.  One more term of either x or y occurs as the divider fence length.  You are not clear about running this subdividor accross the middle.  Diagonally, or perpendicularly?  \r<BR>\n" );
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document.write( "I am choosing the diagonal, because now no need to look at choice of either x or y.  The total fence length using variables would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B2y%2Bdiagonal=3000 ALIGN=MIDDLE  ALT=\"2x%2B2y%2Bdiagonal=3000\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "That diagonal is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2=d%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2=d%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=sqrt%28x%5E2%2By%5E2%29 ALIGN=MIDDLE  ALT=\"d=sqrt%28x%5E2%2By%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So fencing length is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B2y%2Bsqrt%28x%5E2%2By%5E2%29=3000 ALIGN=MIDDLE  ALT=\"2x%2B2y%2Bsqrt%28x%5E2%2By%5E2%29=3000\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the area is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=xy=A ALIGN=MIDDLE  ALT=\"xy=A\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Solve the fence length equation for either x or y.<BR>\n" );
document.write( "sqrt(x^2+y^2)=3000-2x-2y<BR>\n" );
document.write( "x^2+y^2=(3000-2(x+y))^2<BR>\n" );
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document.write( "Excuse me.  This is easier to do on paper than in text form typed into a website page.  \r<BR>\n" );
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document.write( "The plan is solve the fencing equation for either x or y, substitute this into the Area equation or function, and then find the derivative; and set equal to zero and solve for the variable.  Then calculate the other variable. </SPAN>\n" );
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