document.write( "Question 68606: pLEASE HELP ME WITH THIS PROBLEM\r
\n" ); document.write( "\n" ); document.write( "If 2x-4y=-2 and 3x-2y=3 then 2y+x =
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Algebra.Com's Answer #48832 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
If 2x-4y=-2 and 3x-2y=3 then 2y+x =
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\n" ); document.write( "Solve the system using the first two equations:
\n" ); document.write( "2x - 4y = -2
\n" ); document.write( "3x - 2y = 3
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\n" ); document.write( "Multiply the 2nd equation by 2 and subtract it from equation 1:
\n" ); document.write( "2x - 4y = -2
\n" ); document.write( "6x - 4y = 6
\n" ); document.write( "---------------subtracting eliminates y
\n" ); document.write( "-4x + 0 = -8
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\n" ); document.write( "Divide both sides by -4
\n" ); document.write( "1x = -8/-4
\n" ); document.write( "x = + 2
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\n" ); document.write( "Find y using the 1st equation, substitute 2 for x:
\n" ); document.write( "2x - 4y = -2
\n" ); document.write( "2(2) - 4y = -2
\n" ); document.write( "4 - 4y = - 2
\n" ); document.write( "-4y = -2 - 4
\n" ); document.write( "-4y = -6
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\n" ); document.write( "Divide both sides by -4
\n" ); document.write( "1y - -6/-4
\n" ); document.write( "y = +1.5
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\n" ); document.write( "Check our solution by substituting for x & y in the 2nd equation:
\n" ); document.write( "3x - 2y = 3
\n" ); document.write( "3(2) - 2(1.5) = 3
\n" ); document.write( "6 - 3 = 3 proves our solutions are right:
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\n" ); document.write( "Now complete the last equation 2y + x =, substitute for x & y
\n" ); document.write( "2(1.5) + 2 =
\n" ); document.write( "3 + 2 = 5
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\n" ); document.write( "The equation should be 2y + x = 5
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\n" ); document.write( "A lot of steps, but each one was simple, if you study it carefully, it will all
\n" ); document.write( "make sense to you\r
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