document.write( "Question 810632: in 5 hours how far can a car go and return if the average speed going is 48 mph and the average speed returning is 52 mph.\r
\n" ); document.write( "\n" ); document.write( "Can u pls draw a table how u worked it out and also a diagram pls thank you \n" ); document.write( "
Algebra.Com's Answer #488290 by stanbon(75887)\"\" \"About 
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In 5 hours how far can a car go and return if the average speed going is 48 mph and the average speed returning is 52 mph.
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\n" ); document.write( "Going DATA:
\n" ); document.write( "time = x hrs ; rate = 48 mph ; distance = 48x miles
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\n" ); document.write( "Returning DATA:
\n" ); document.write( "time = 5-x hrs ; rate = 52 mph ; distance = 52(5-x) = 260-52x miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance going = distance returning
\n" ); document.write( "48x = 260-52x
\n" ); document.write( "100x = 260
\n" ); document.write( "x = 2.6 hrs
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\n" ); document.write( "Total distance = 48x+(260-52x) = 260-4x = 260-4*2.6 = 249.6 miles
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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