document.write( "Question 68579: P=12 units:Bottom (x-1),side 5,side x\r
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document.write( "This is one of the harder eqautions for me.\r
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document.write( "Help would not only be appreciated,but desired\r
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document.write( "Thank you:) \n" );
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Algebra.Com's Answer #48829 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! P=12 units:Bottom (x-1),side 5,side x \n" ); document.write( ": \n" ); document.write( "I understand this to mean the perimeter of a triangle, with the given sides = 12 \n" ); document.write( ": \n" ); document.write( "The perimeter is the sum of all 3 sides: \n" ); document.write( "(x-1) + 5 + x = 12 \n" ); document.write( ": \n" ); document.write( "Add the x's, \n" ); document.write( "x + x - 1 + 5 = 12 \n" ); document.write( ": \n" ); document.write( "2x + 4 = 12 \n" ); document.write( ": \n" ); document.write( "Subtract 4 from both sides: \n" ); document.write( "2x = 12 - 4 \n" ); document.write( ": \n" ); document.write( "2x = 8 \n" ); document.write( ": \n" ); document.write( "Divide both sides by 2 and you have: \n" ); document.write( "x = 8/2 \n" ); document.write( ": \n" ); document.write( "x = 4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check our solution, substitute 4 for x: (4-1) + 5 + 4 = 12 \n" ); document.write( " |