document.write( "Question 810614: A new game show requires a playing ﬁeld with a perimeter of
\n" ); document.write( "54 yards and length 3 yards less than twice the width. What are
\n" ); document.write( "the dimensions? \n" ); document.write( "

Algebra.Com's Answer #488285 by TimothyLamb(4379) $\"\"$ $\"About$

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54 = 2L + 2W
\n" ); document.write( "L = 2W - 3
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\n" ); document.write( "54 = 2L + 2W
\n" ); document.write( "54 = 2(2W - 3) + 2W
\n" ); document.write( "54 = 4W - 6 + 2W
\n" ); document.write( "60 = 6W
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\n" ); document.write( "W = 10
\n" ); document.write( "L = 17
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