document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68592>Question 68592</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Please help to solve\r<BR>\n" );
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document.write( "One solution was 10% alcohol and the other was 30% alcohol. HOw much of each should be used to get 200 gallons of a solution that is  17% alcohol? </SPAN>\n" );
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document.write( "Let x= amount of 30% alcohol\r<BR>\n" );
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document.write( "Then 200-x=amount of 10% alcohol\r<BR>\n" );
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document.write( "Now we know that the amount of pure alcohol in the 10% solution 0.10(200-x) plus the amount of pure alcohol in the 30% solution 0.30x equals the amount of pure alcohol in the final mixture 0.17(200).  So our equation to solve is:\r<BR>\n" );
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document.write( "0.10(200-x)+0.30x=0.17(200)  clear parens\r<BR>\n" );
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document.write( "20-0.10x+0.30x=34  subtract 20 from both sides\r<BR>\n" );
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document.write( "+0.20x=14<BR>\n" );
document.write( "x=70 gal of 30% alcohol\r<BR>\n" );
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document.write( "200-x=200-70=130 gal of 10% alcohol\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "70(0.3)+130(0.1)=200(.17)\r<BR>\n" );
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document.write( "21+13=34<BR>\n" );
document.write( "34=34\r<BR>\n" );
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document.write( "Hope this helps --------ptaylor </SPAN>\n" );
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