document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=810532>Question 810532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there is to be a water fountion in the back yard of the buliding. the water tap is 25 feet away from the proposed fountaion location at a bearing of 75 dregress. however becaue of the construction of the garage the water pipe extends 10 feet out at a 90 dergree bearing before turning towards the fountaion . what is the length of the pipe needed from the end of the fountain? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488218 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there is to be a water fountain in the back yard of the buliding. the water tap is 25 feet away from the proposed fountain location at a bearing of 75 dregress. however because of the construction of the garage the water pipe extends 10 feet out at a 90 degree bearing before turning towards the fountain . what is the length of the pipe needed from the end of the fountain?<BR>\n" );
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document.write( "Draw the picture on a coordinate system.<BR>\n" );
document.write( "Put the tap (T) at the origin.<BR>\n" );
document.write( "Mark an angle of 75degrees up from the positive x-axis.<BR>\n" );
document.write( "Let the fountain(F) be on that 75 degree bearing line and 25 ft. from T.<BR>\n" );
document.write( "Draw a line segment from T to (0,10) on the y-axis.<BR>\n" );
document.write( "Draw a line segment from (0,10) to F and label it \"x\".<BR>\n" );
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document.write( "Solve for \"x\" using the Law of Cosines::<BR>\n" );
document.write( "x^2 = 10^2+25^2-2*10*25*cos(15 degrees)<BR>\n" );
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document.write( "x^2 = 235.93<BR>\n" );
document.write( "x = 15.36 ft<BR>\n" );
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document.write( "Total pipe needed: 10'+15.36 = 25.36 ft.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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