document.write( "Question 810521: Daniel leaves school and runs 5 miles to his friend's house where he had left his bike the previous day. After picking up his bike, he then rides a distance of 2 miles to his home. His running speed is 3 mph slower than his biking speed. His total running and biking time is 2 hours. What is Daniel's biking speed? \n" ); document.write( "
Algebra.Com's Answer #488212 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! x+y=2, \n" ); document.write( "r=b-3, \n" ); document.write( "5/r=x, \n" ); document.write( "2/b=y \n" ); document.write( "b=bike speed = 6, y= bike time= 1/3 check 6*1/3=2 miles \n" ); document.write( "r=running speed = 3, x=running time= 5/3, check 5/3*3=5 miles \n" ); document.write( "check 1/3+5/3=6/3=2 hours \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |