document.write( "Question 810521: Daniel leaves school and runs 5 miles to his friend's house where he had left his bike the previous day. After picking up his bike, he then rides a distance of 2 miles to his home. His running speed is 3 mph slower than his biking speed. His total running and biking time is 2 hours. What is Daniel's biking speed? \n" ); document.write( "
Algebra.Com's Answer #488212 by richwmiller(17219)\"\" \"About 
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x+y=2,
\n" ); document.write( "r=b-3,
\n" ); document.write( "5/r=x,
\n" ); document.write( "2/b=y
\n" ); document.write( "b=bike speed = 6, y= bike time= 1/3 check 6*1/3=2 miles
\n" ); document.write( "r=running speed = 3, x=running time= 5/3, check 5/3*3=5 miles
\n" ); document.write( "check 1/3+5/3=6/3=2 hours \r
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