document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8970>Question 8970</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the lenght of a picture frame is 3 in. greater than the width. the perimeter is less than 52 in.Describe the dimensions of the frame.\r<BR>\n" );
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document.write( "please help me out and thank you.... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4882 by </B><A HREF=/tutors/aboutme.mpl?userid=not_da_brightest_bulb><B>not_da_brightest_bulb(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=not_da_brightest_bulb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK sweetie........because perimeter is the sum of numbers on all 4 sides, I would first divide 4 into 52. That would give me 13, but I need to divide that by 2 because the width is the same on both sides ofcourse. That would give me 5.6 which I would round to 6. I then multiplied 6 by 3 and got 18. The perimeter would = to 48 which is below 52.  </SPAN>\n" );
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