document.write( "Question 810366: Sam invested $1950,part of it at 6% and the rest at 8%,yearly interest. The yearly income on the 8% investment was $6 more than twice the income from 6% investment. How much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #488176 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Sam invested $1950,part of it at 6% and the rest at 8%,yearly interest. The yearly income on the 8% investment was $6 more than twice the income from 6% investment. How much did he invest at each rate?\r \n" ); document.write( "\n" ); document.write( "let part I at 6% be x \n" ); document.write( "Part II at 8% will be (1850-x)\r \n" ); document.write( "\n" ); document.write( "Interest on 8% = 8%(1950-x) \n" ); document.write( "Interest on 6% = 6%x \n" ); document.write( "twice = 2*6%x\r \n" ); document.write( "\n" ); document.write( "8%(1950-x)- 12%x=6\r \n" ); document.write( "\n" ); document.write( "multiply by 100 \n" ); document.write( "8(1950-x)-12x=600 \n" ); document.write( "15600-8x-12x=600 \n" ); document.write( "20x=15600-600 \n" ); document.write( "20x=15000 \n" ); document.write( "x= 15000/20\r \n" ); document.write( "\n" ); document.write( "x= 7500 @ 6% \n" ); document.write( "balance at 8% \n" ); document.write( " |