document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=810437>Question 810437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a train cover s distance in 50 mins , if it runs at a speed of 48kmph .the speed at which must run to reduce the time to 40 mins ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488174 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let distance be x\r<BR>\n" );
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document.write( "t=d/r\r<BR>\n" );
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document.write( "x/48 = 5/6 hours<BR>\n" );
document.write( "x=48*5/6<BR>\n" );
document.write( "=40\r<BR>\n" );
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document.write( "let y be the required speed to reduce the time<BR>\n" );
document.write( "plug x<BR>\n" );
document.write( "x/y = 2/3 hours\r<BR>\n" );
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document.write( "40/y = 2/3\r<BR>\n" );
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document.write( "y=3*40/2\r<BR>\n" );
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document.write( "y= 60 km/h\r<BR>\n" );
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document.write( " </SPAN>\n" );
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