document.write( "Question 810405: Find all solutions t in the interval [0 , 2pi] to the equation sin(2t) = square root of 2 cos (t) \n" ); document.write( "
Algebra.Com's Answer #488101 by lwsshak3(11628)\"\" \"About 
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Find all solutions t in the interval [0 , 2pi] to the equation sin(2t) = square root of 2 cos (t)
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\n" ); document.write( "sin(2t)=√2cos(t)
\n" ); document.write( "2sin(t)cos(t)=√2cos(t)
\n" ); document.write( "square both sides
\n" ); document.write( "4sin^2(t)cos^2(t)=2cos^2(t)
\n" ); document.write( "divide by 2
\n" ); document.write( "2sin^2(t)cos^2(t)=cos^2(t)
\n" ); document.write( "divide by cos^2(t)
\n" ); document.write( "2sin^2(t)=1
\n" ); document.write( "sin^2(t)=1/2
\n" ); document.write( "sin(t)=±√(1/2)=±√2/2
\n" ); document.write( "t=π/4, 3π/4, 5π/4, 7π/4 \n" ); document.write( "
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