document.write( "Question 810274: Mrs mitchell put a total of 10000 dls in two accounts. One account sarna 6% simple annual interest. The other earns 6.5% simple interest . After 1 year the two accounts earned 632.50 interest. Find how much money was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #488054 by mananth(16946)\"\" \"About 
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Part I 6.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 6.50% per annum ------------ Amount invested = y
\n" ); document.write( " 10000
\n" ); document.write( "Interest----- 632.50
\n" ); document.write( "
\n" ); document.write( "Part I 6.00% per annum ---x
\n" ); document.write( "Part II 6.50% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 10000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "6.00% x + 6.50% y= 632.5
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6 x + 6.5 y= 63250.00 --------2
\n" ); document.write( "Multiply (1) by -6
\n" ); document.write( "we get
\n" ); document.write( "-6 x -6 y= -60000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 0.5 y= 3250
\n" ); document.write( "divide by 0.5
\n" ); document.write( " y = 6500
\n" ); document.write( "Part I 6.00% dls 3500
\n" ); document.write( "Part II 6.50% dls 6500
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\n" ); document.write( "CHECK
\n" ); document.write( "3500 --------- 6.00% ------- 210.00
\n" ); document.write( "6500 ------------- 6.50% ------- 422.50
\n" ); document.write( "Total -------------------- 632.50
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\n" ); document.write( "m.ananth@hotmail.ca
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