document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=809689>Question 809689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many cubic centimeters of a 20% saline solution should be added to 20 cubic centimeters of a 60% saline solution to create a 30% saline solution? If necessary, round to the nearest tenth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #487895 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=487895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How many cubic centimeters of a 20% saline solution should be added to 20 cubic centimeters of a 60% saline solution to create a 30% saline solution?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "let x = amt of 20% solution to accomplish this<BR>\n" );
document.write( ":<BR>\n" );
document.write( ".60(20) + .20x = .30(x+20)<BR>\n" );
document.write( "12 + .20x = .30x + 6<BR>\n" );
document.write( "12 - 6 = .30x - .20x<BR>\n" );
document.write( ".10x = 6<BR>\n" );
document.write( "x = 6/.1<BR>\n" );
document.write( "x = 60 cu/cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );