document.write( "Question 809730: A 20% acid solution is mixed with a 70% acid solution to get 50 liters of a 40% solution.\r
\n" ); document.write( "\n" ); document.write( "How much of the 70% solution is used?\r
\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "\n" ); document.write( "Going against the current, a boat takes 6 hours to make a 120-mile trip. When the boat travels with the current on the return trip, it takes 5 hours.\r
\n" ); document.write( "\n" ); document.write( "If x = the rate of the boat in still water and y = the rate of the current, which of the following systems could be used to solve the problem?\r
\n" ); document.write( "\n" ); document.write( "a.) 6(x - y) = 120 and 5(x + y) = 120
\n" ); document.write( "b.) 6(x + y) = 120 and 5(x - y) = 120
\n" ); document.write( "c.) 6x - 5y = 120 and x + y = 120
\n" ); document.write( "

Algebra.Com's Answer #487744 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+a+\" = liters of 20% solution needed
\n" ); document.write( "Let \"+b+\" = liters of 70% solution needed
\n" ); document.write( "(1) \"+a+%2B+b+=+50+\"
\n" ); document.write( "(2) \"+%28+.2a+%2B+.7b+%29+%2F+50+=+.4+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "(2) \"+.2a+%2B+.7b+=+.4%2A50+\"
\n" ); document.write( "(2) \"+.2a+%2B+.7b+=+20+\"
\n" ); document.write( "(2) \"+2a+%2B+7b+=+200+\"
\n" ); document.write( "Multiply both sides of (1) by \"2\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"+2a+%2B+7b+=+200+\"
\n" ); document.write( "(1) \"+-2a+-2b+=+-100+\"
\n" ); document.write( "\"+5b+=+100+\"
\n" ); document.write( "\"+b+=+20+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+a+%2B+b+=+50+\"
\n" ); document.write( "(1) \"+a+=+30+\"
\n" ); document.write( "30 liters of 20% solution are needed
\n" ); document.write( "20 liters of 70% solution are needed
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+.2%2A30+%2B+.7%2A20+%29+%2F+50+=+.4+\"
\n" ); document.write( "(2) \"+%28+6+%2B+14+%29+%2F+50+=+.4+\"
\n" ); document.write( "(2) \"+20+=+.4%2A50+\"
\n" ); document.write( "(2) \"+20+=+20+\"
\n" ); document.write( "OK
\n" ); document.write( "----------------------------
\n" ); document.write( "(a) is the answer
\n" ); document.write( "\"+d+=+r%2At+\"
\n" ); document.write( "Subtract the rate of the current from the rate of the boat
\n" ); document.write( "in still water when going against the current
\n" ); document.write( "---------
\n" ); document.write( "Add the 2 rates when going with the current
\n" ); document.write( "
\n" ); document.write( "
\n" );