document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=809599>Question 809599</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the question is to find the numerical value of one trigonometric function of x and the problem is      cscx=sinxtanx+cosx    but only working with one side (the harder side) what are my steps?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #487731 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=487731\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the numerical value of one trigonometric function of x and the problem is cscx=sinxtanx+cosx <BR>\n" );
document.write( "-----<BR>\n" );
document.write( "csc(x) = (sin(x))*(sin/cos) + cos<BR>\n" );
document.write( "----<BR>\n" );
document.write( "csc(x) = (sin^2(x)+cos^2(x)/cos(x)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "csc(x) = 1/cos(x)<BR>\n" );
document.write( "========<BR>\n" );
document.write( "Note: The right side is the secant, not the cosecant.<BR>\n" );
document.write( "================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );