Algebra.Com's Answer #487718 by Edwin McCravy(20059)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
Please help me with this Calculus II question:
\n" );
document.write( " Find all points of intersection of the given curves. (Assume
\n" );
document.write( " 0 ≤ θ ≤ 2π.
\n" );
document.write( "Order your answers from smallest to largest θ. If an intersection occurs at the pole, enter POLE in the first answer blank.)
\n" );
document.write( " r = 1 − cos θ, r = 1 + sin θ
\n" );
document.write( "\r\n" );
document.write( " 1 − cos θ = 1 + sin θ , since both = r\r\n" );
document.write( " −cos θ = sin θ\r\n" );
document.write( "Divide both sides by cos θ\r\n" );
document.write( "  =  \r\n" );
document.write( " -1 = tan(θ)\r\n" );
document.write( "\r\n" );
document.write( " \r\n" );
document.write( "So θ has two possible values where 0 ≤ θ ≤ 2π. the tangent is negative\r\n" );
document.write( "in Q2 and Q4 and the reference angle is 45° or  , so θ is  \r\n" );
document.write( "in Q2 or  in Q4.\r\n" );
document.write( " \r\n" );
document.write( "So the smaller value of θ is , and the value of r is gotten\r\n" );
document.write( "by substituting for θ in either of the original equations:\r\n" );
document.write( "r = 1 − cos θ = 1 - cos = 1 -  = 1 +  =  \r\n" );
document.write( "So the first point is (r,θ) = (, )\r\n" );
document.write( "The larger value of θ is , and the value of r is gotten\r\n" );
document.write( "by substituting for θ in either of the original equations:\r\n" );
document.write( "r = 1 − cos θ = 1 - cos = 1 -  = 1 - =  \r\n" );
document.write( "So the second point is (r,θ) = (, )\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" );
document.write( " \n" );
document.write( " |