document.write( "Question 808961: the tens digit of a three-digit number is 3 less than 5 times the unit digit. three times the sum of the digits is 2 more than 4 times the hundreds digit. if the digits are reversed, the new number is 549 less than than the original number. what is the original number? \n" ); document.write( "
Algebra.Com's Answer #487648 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a = the 100's digit \n" ); document.write( "b = the 10's \n" ); document.write( "c = the units \n" ); document.write( "then \n" ); document.write( "100a+10b+c = the number \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\" the tens digit of a three-digit number is 3 less than 5 times the unit digit.\" \n" ); document.write( "b = (5c-3)\r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( "\" three times the sum of the digits is 2 more than 4 times the hundreds digit.\" \n" ); document.write( "3(a+b+c) = 4a + 2 \n" ); document.write( "3a + 3b + 3c = 4a + 2 \n" ); document.write( "3a - 4a + 3b + 3c = 2 \n" ); document.write( "-a + 3b + 3c = 2 \n" ); document.write( ": \n" ); document.write( "\"if the digits are reversed, the new number is 594 less than than the original number.\" \n" ); document.write( "100c + 10b + a = 100a + 10b + c - 594 \n" ); document.write( "100c - c + 10c - 10c + a - 100a = -594 \n" ); document.write( "99c - 99a = -594 \n" ); document.write( "simplify, divide by 99 \n" ); document.write( "c - a = -6 \n" ); document.write( "mult by -1 \n" ); document.write( "a - c = 6 \n" ); document.write( "a = (c+6) \n" ); document.write( ": \n" ); document.write( "Now we have three equations \n" ); document.write( "b = (5c-3); -a + 3b + 3c = 2; a = (c+6) \n" ); document.write( "In the middle equation, replace a and b \n" ); document.write( "-(c+6) + 3(5c-3) + 3c = 2 \n" ); document.write( "-c - 6 + 15c - 9 + 3c = 2 \n" ); document.write( "Combine like terms \n" ); document.write( "17c - 15 = 2 \n" ); document.write( "17c = 2 + 15 \n" ); document.write( "17c = 17 \n" ); document.write( "c = 1 \n" ); document.write( "then \n" ); document.write( "b = 5(1) - 3 \n" ); document.write( "b = 2 \n" ); document.write( "and \n" ); document.write( "a = 1 + 6 \n" ); document.write( "a = 7 \n" ); document.write( ": \n" ); document.write( "Our number then is 721 \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Check this in the 3rd statement: \n" ); document.write( "127 = 721 - 594 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |