document.write( "Question 809378: Solve each equation for solutions over the interval [0,2pi).\r
\n" ); document.write( "\n" ); document.write( "2tanx - 1 = 0\r
\n" ); document.write( "\n" ); document.write( "I did x = tan^-1(1/2)but I did not get the right answer. \r
\n" ); document.write( "\n" ); document.write( "Correct answer: {0.463647609,3.605240263}\r
\n" ); document.write( "\n" ); document.write( "Could you please explain how to solve this and these types of problems? I am having a really hard time understanding this.\r
\n" ); document.write( "\n" ); document.write( "Thanks!
\n" ); document.write( "

Algebra.Com's Answer #487591 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"2%2Atan%28x%29-+1+=+0\"
\n" ); document.write( "\"2%2Atan%28x%29=1\"
\n" ); document.write( "\"tan%28x%29=1%2F2\"
\n" ); document.write( "The calculator would tell you that \"tan%5E%28-1%29%280.5%29=0.463647609\" in radians,
\n" ); document.write( "or \"tan%5E%28-1%29%280.5%29=26.56505118%5Eo\" in degrees.
\n" ); document.write( "That is because the inverse function of tangent is defined as the angle that has that tangent and is between \"-pi%2F2\" and \"pi%2F2\" in radians,
\n" ); document.write( "or between \"-90%5Eo\" and \"90%5Eo\" in degrees.
\n" ); document.write( "However, the function tangent has a period of \"pi\" radians (or \"180%5Eo\" in degrees.
\n" ); document.write( "That means, in other words, that \"tan%28x%2Bpi%29=tan%28x%29\" .
\n" ); document.write( "That gives you the other solution,
\n" ); document.write( "\"x=0.463647609%2Bpi=3.605240263\"
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