document.write( "Question 808898: tom is older than his brother. The product of their ages 6 years from now will be 120 more than the product of their present ages. Find each of their ages \n" ); document.write( "
Algebra.Com's Answer #487450 by ankor@dixie-net.com(22740)\"\" \"About 
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tom is older than his brother.
\n" ); document.write( " The product of their ages 6 years from now will be 120 more than the product of their present ages.
\n" ); document.write( "(t+6)(b+6) = tb + 120
\n" ); document.write( "FOIL
\n" ); document.write( "tb + 6t + 6b + 36 = tb + 120
\n" ); document.write( "Subtract tb from both sides
\n" ); document.write( "6t + 6b + 36 = 120
\n" ); document.write( "simplify, divide by 6
\n" ); document.write( "t + b + 6 = 20
\n" ); document.write( "t + b = 20-6
\n" ); document.write( "t + b = 14
\n" ); document.write( ":
\n" ); document.write( " Find each of their ages
\n" ); document.write( "Several possibilities
\n" ); document.write( " T B
\n" ); document.write( "13 1
\n" ); document.write( "12 2
\n" ); document.write( "11 3
\n" ); document.write( "10 4
\n" ); document.write( "9 5
\n" ); document.write( "8 6
\n" ); document.write( " \n" ); document.write( "
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