document.write( "Question 809041: 1.Find two consecutive integers such that the sum of one-fourth of the first and one-fifth of the second is 11.\r
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document.write( "2. The denominator of a certain fraction is 6 more than the numerator, and the fraction is equivalent to one-third. Find the numerator. \n" );
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Algebra.Com's Answer #487366 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the integers be x & x+1\r \n" ); document.write( "\n" ); document.write( "x/4 = (x+1)/5 =11\r \n" ); document.write( "\n" ); document.write( "multiply equation by 20\r \n" ); document.write( "\n" ); document.write( "5x+4(x+1)=220\r \n" ); document.write( "\n" ); document.write( "5x+4x+4 =220 \n" ); document.write( "9x+4=220 \n" ); document.write( "9x=216 \n" ); document.write( "x=24\r \n" ); document.write( "\n" ); document.write( "24,25\r \n" ); document.write( "\n" ); document.write( "------------\r \n" ); document.write( "\n" ); document.write( "x/(x+6) =1/3\r \n" ); document.write( "\n" ); document.write( "cross multiply\r \n" ); document.write( "\n" ); document.write( "3x=x+6 \n" ); document.write( "3x-x=6 \n" ); document.write( "2x=6 \n" ); document.write( "x=3\r \n" ); document.write( "\n" ); document.write( "numerator =3 \n" ); document.write( "denominator = 3+6 =9 \r \n" ); document.write( "\n" ); document.write( "fraction 3/9 \n" ); document.write( " |