document.write( "Question 809009: The sum\r
\n" );
document.write( "\n" );
document.write( "1 - 2 + 3 - 4 + ... + 65 - 66 + 67\r
\n" );
document.write( "\n" );
document.write( "is \n" );
document.write( "
Algebra.Com's Answer #487358 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 1 - 2 + 3 - 4 + ... + 65 - 66 + 67\r \n" ); document.write( "\n" ); document.write( "let us break it up into two sequences\r \n" ); document.write( "\n" ); document.write( "both are arithmetic progressions\r \n" ); document.write( "\n" ); document.write( "1+3+5..........67\r \n" ); document.write( "\n" ); document.write( "a=1,d=2 Tn=67\r \n" ); document.write( "\n" ); document.write( "67=1+(n-1)2 \n" ); document.write( "67=1+2n-2 \n" ); document.write( "2n=68 \n" ); document.write( "n=34\r \n" ); document.write( "\n" ); document.write( "Sn = n/2(2a+(n-1)d) \n" ); document.write( "=(34/2(2*1+(37-1)2) \n" ); document.write( "=17*(2+36*2) \n" ); document.write( "=17*74 \n" ); document.write( "=1258\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and -2,-4,-6......-66\r \n" ); document.write( "\n" ); document.write( "a=-2, d=-2 Tn= -66\r \n" ); document.write( "\n" ); document.write( "-66=-2+(n-1)*-2\r \n" ); document.write( "\n" ); document.write( "-66=-2-2n+2\r \n" ); document.write( "\n" ); document.write( "n=33\r \n" ); document.write( "\n" ); document.write( "S33= 33/2( 2*-2+(33-1)*-2)\r \n" ); document.write( "\n" ); document.write( "S33=33/2(-4-64)\r \n" ); document.write( "\n" ); document.write( "S33=33/2 * -68\r \n" ); document.write( "\n" ); document.write( "=33*-34 \n" ); document.write( "=-1122\r \n" ); document.write( "\n" ); document.write( "1258-1122\r \n" ); document.write( "\n" ); document.write( "=136 \n" ); document.write( " |