document.write( "Question 809005: The length of a rectangle is 3yd less than double the width, and the area of the rectangle is 44yd^2. Find the dimensions of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #487339 by vheroli(126) $\"\"$ $\"About$

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Where:
\n" ); document.write( "L= length
\n" ); document.write( "W= width
\n" ); document.write( "x= variable
\n" ); document.write( "A= area\r
\n" ); document.write( "\n" ); document.write( "Formulas:
\n" ); document.write( "A= L*W
\n" ); document.write( "L= 2x-3
\n" ); document.write( "W= x\r
\n" ); document.write( "\n" ); document.write( "Solution:
\n" ); document.write( "44= (2x-3) * (x): Distribute x
\n" ); document.write( " $\"44=+2x%5E2+-+3x\"$ : Notice that the equation could be factor out.
\n" ); document.write( " $\"+2x%5E2+-+3x+-+44+=+0+\"$ : Factor out
\n" ); document.write( "= (x+4) (2x-11) : Reject the factor (x+4) because it is negative.\r
\n" ); document.write( "\n" ); document.write( "Therefore we will use the factor (2x-11) to get the answer:
\n" ); document.write( "2x-11=0
\n" ); document.write( "2x=11
\n" ); document.write( "x= 11/2
\n" ); document.write( "x= 5.5\r
\n" ); document.write( "\n" ); document.write( "Substitute the x to get the answers from our previous Formulas:
\n" ); document.write( "L= 2x-3
\n" ); document.write( "L= 2(5.5)-3
\n" ); document.write( "L= 8 yd\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "W= x
\n" ); document.write( "W= 5.5 yd \n" ); document.write( "

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