document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68495>Question 68495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An ecoli bacteria divides every 20 minutes. After 120 minutes how many ecoli bacteria are there? Solve algebraically. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48729 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An ecoli bacteria divides every 20 minutes. After 120 minutes how many ecoli bacteria are there? Solve algebraically.<BR>\n" );
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document.write( "A(t) = Ao (2)^(t/20)<BR>\n" );
document.write( "Assuming you start with 1 bacteria you get:<BR>\n" );
document.write( "A(120)=1(2)^(120/20)<BR>\n" );
document.write( "=2^6=64<BR>\n" );
document.write( "That is the number generated in the last 20 minutes.<BR>\n" );
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document.write( "The total number = 1+2+4+....+64<BR>\n" );
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document.write( "This is a geometric series with seven terms, a(1)=1, r=2:<BR>\n" );
document.write( "S(7)= [r^(8)-1}/[r-1]= 127<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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