document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=808540>Question 808540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use a double- or half-angle formula to determine the value of the trigonometric function. sin(19pi/12)\r<BR>\n" );
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document.write( "How to do this? Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #487280 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=487280\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use a double- or half-angle formula to determine the value of the trigonometric function. sin(19pi/12) <BR>\n" );
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document.write( "Note:: 19pi/12 is in QIV where the sine is negative::<BR>\n" );
document.write( "Reference angle:: (5/12)pi = 75 degrees<BR>\n" );
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document.write( "So sin[19pi/12] = -sin[75 degrees] = -sin[150/2] = -sqrt[(1-cos(150)/2]<BR>\n" );
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document.write( "= -sqrt[(1+sqrt(3)/2)/2]<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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