document.write( "Question 808869: A parabola has a axis of symmetry x=2 and passes through the points (0,7) and (-1,-3) what is its equation? \n" ); document.write( "
Algebra.Com's Answer #487266 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "In order to find the equation of a parabola, you need at least 3 points on the parabola. We are given 2 points. However, because of symmetry, we know that there is a point with a function value of 7 equidistant from the axis of symmetry x = 2 on the horizontal line y = 7. So we have a third point (4,7) -- since (0,7) is 2 distant from x = 2, we need a point 2 units on the other side, namely (4,7).\r
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\n" ); document.write( "\n" ); document.write( "Note that we could also have chosen the point (-5,-3) and achieved the same result.\r
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\n" ); document.write( "\n" ); document.write( "The equation of a general quadratic function is:\r
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\n" ); document.write( "\n" ); document.write( "So if the function value is 7 when x = 0, which is what the point (0,7) means, then\r
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\n" ); document.write( "\n" ); document.write( "Hence, \r
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\n" ); document.write( "\n" ); document.write( "Also, since the point (-1,-3) is on the graph,\r
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\n" ); document.write( "\n" ); document.write( "But since we know that , we can say:\r
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\n" ); document.write( "\n" ); document.write( "And since the point (4,7) is on the graph,\r
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\n" ); document.write( "\n" ); document.write( "But since we know that , we can say:\r
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\n" ); document.write( "\n" ); document.write( "Now all you have to do is to solve the 2X2 system:\r
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\n" ); document.write( "\n" ); document.write( "and then once you know the values of a and b to go along with the value of c you already know, you can make the substitutions into\r
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\n" ); document.write( "\n" ); document.write( "and you will have your desired function.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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