document.write( "Question 808614: If two taps A and B are turned on together, they will fill a tank in 1 hour and 20 minutes. If tap A is turned on for 10 minutes and then tap B is turned on for 12 minutes, only 2/15 of the tank is filled. How long does each tap take to fill the tank alone? \n" ); document.write( "
Algebra.Com's Answer #487227 by ankor@dixie-net.com(22740)\"\" \"About 
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If two taps A and B are turned on together, they will fill a tank in 1 hour and 20 minutes.
\n" ); document.write( "Change this to 80 minutes
\n" ); document.write( "Let the full tank = 1
\n" ); document.write( "The shared work equation
\n" ); document.write( "\"80%2Fa+\" + \"80%2Fb\" = 1
\n" ); document.write( "multiply by ab, resulting in
\n" ); document.write( "80b + 80a = ab
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\n" ); document.write( "If tap A is turned on for 10 minutes and then tap B is turned on for 12 minutes, only 2/15 of the tank is filled.
\n" ); document.write( "\"10%2Fa\" + \"12%2Fb\" = \"2%2F15\"
\n" ); document.write( "multiply by 15ab, resulting in:
\n" ); document.write( "15b(10) + 15a(12) = 2ab
\n" ); document.write( "150b + 180a = 2ab
\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "75b + 90a = ab
\n" ); document.write( "ab = ab therefore
\n" ); document.write( "75b + 90a = 80b + 80a
\n" ); document.write( "90a - 80a = 80b - 75b
\n" ); document.write( "10a = 5b
\n" ); document.write( "divide by 5
\n" ); document.write( "2a = b
\n" ); document.write( "Use the 1st equation, replace b with 2a
\n" ); document.write( "\"80%2Fa+\" + \"80%2F%282a%29\" = 1
\n" ); document.write( "multiply by 2a
\n" ); document.write( "2(80) + 80 = 2a
\n" ); document.write( "240 = 2a
\n" ); document.write( "a = 240/2
\n" ); document.write( "a = 120 min tap A alone
\n" ); document.write( "then
\n" ); document.write( "2(120) = 240 min tap B alone
\n" ); document.write( ":
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\n" ); document.write( "Check this on a calc
\n" ); document.write( "\"10%2F120\" + \"12%2F240\" = \"2%2F15\"\r
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