document.write( "Question 808689: roger can run one mile in 21 minutes. jeff can run 1 mile in 18 minutes. if jeff gives roger a 1 minute head start, how long will it take before jeff catches up to roger? how far will each have run? \n" ); document.write( "
Algebra.Com's Answer #487151 by josgarithmetic(39616)\"\" \"About 
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Let m = minutes Roger runs.
\n" ); document.write( "Let d = distance until Roger and Jeff ran the same distance.\r
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\n" ); document.write( "\n" ); document.write( "Runner___________speed(mile/minute)_____time__________distance
\n" ); document.write( "Jeff_____________1/21____________________m+1___________d=(1/21)(m+1)
\n" ); document.write( "Roger____________1/18____________________m_____________d=(1/18)m\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F21%29%28m%2B1%29=%281%2F18%29%28m%29\"
\n" ); document.write( "Solve for m. With this, find m+1, the time for Jeff to catchup to Roger. Use m to find the value for the distance, d.\r
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