document.write( "Question 808689: roger can run one mile in 21 minutes. jeff can run 1 mile in 18 minutes. if jeff gives roger a 1 minute head start, how long will it take before jeff catches up to roger? how far will each have run? \n" ); document.write( "
Algebra.Com's Answer #487151 by josgarithmetic(39616)![]() ![]() ![]() You can put this solution on YOUR website! Let m = minutes Roger runs. \n" ); document.write( "Let d = distance until Roger and Jeff ran the same distance.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Runner___________speed(mile/minute)_____time__________distance \n" ); document.write( "Jeff_____________1/21____________________m+1___________d=(1/21)(m+1) \n" ); document.write( "Roger____________1/18____________________m_____________d=(1/18)m\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Solve for m. With this, find m+1, the time for Jeff to catchup to Roger. Use m to find the value for the distance, d.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |