document.write( "Question 808712: Evaluate the polynomial for x=4 and for x=-4\r
\n" ); document.write( "\n" ); document.write( "2x^2-3x+7
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Algebra.Com's Answer #487148 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "to evaluate the polynomial for \"x=4\" and for \"x=-4\", substitute \"x\" with given value in\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2-3x%2B7\"\r
\n" ); document.write( "\n" ); document.write( "so, if \"x=4\" you will have:\r
\n" ); document.write( "\n" ); document.write( "\"2%284%29%5E2-3%284%29%2B7\"\r
\n" ); document.write( "\n" ); document.write( "=\"2%2A16-12%2B7\"\r
\n" ); document.write( "\n" ); document.write( "=\"32-12%2B7\"\r
\n" ); document.write( "\n" ); document.write( "=\"27\"\r
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\n" ); document.write( "\n" ); document.write( "and, if \"x=-4\" you will have:\r
\n" ); document.write( "\n" ); document.write( "\"2%28-4%29%5E2-3%28-4%29%2B7\"\r
\n" ); document.write( "\n" ); document.write( "=\"2%2A16%2B12%2B7\"\r
\n" ); document.write( "\n" ); document.write( "=\"32%2B12%2B7\"\r
\n" ); document.write( "\n" ); document.write( "=\"51\"\r
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