document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=808602>Question 808602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When a number is added to two thirds of itself the result is 45 .find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #487095 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=487095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number be x\r<BR>\n" );
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document.write( "x+2x/3 =45<BR>\n" );
document.write( "multiply by 3<BR>\n" );
document.write( "3x+2x=3*45\r<BR>\n" );
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document.write( "5x=3*45<BR>\n" );
document.write( "x= 3*45/5\r<BR>\n" );
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document.write( "x=27 </SPAN>\n" );
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