document.write( "Question 808584: Your help would be greatly appreciated.\r
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document.write( "Q1: Two cars left at 0800 from the same point, one travelling east at 50km/h and the other travelling south at 60km/h. At what time will they be 300km apart and using a diagram to show their starting point,respective positions when they are 300km apart, direction, motion and distance travelled.\r
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document.write( "Q2: The distance travelled by both cars after 4hrs from the time they started.\r
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document.write( "Thankyou
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Algebra.Com's Answer #487091 by mananth(16946)![]() ![]() You can put this solution on YOUR website! one car 50 km/h \n" ); document.write( "car II 60 km/h\r \n" ); document.write( "\n" ); document.write( "time they travel = t\r \n" ); document.write( "\n" ); document.write( "car I distance = 50t \n" ); document.write( "car II = 60t\r \n" ); document.write( "\n" ); document.write( "They are moving at right angles to each other\r \n" ); document.write( "\n" ); document.write( "so at any given instant they form a right triangle with origin\r \n" ); document.write( "\n" ); document.write( "50t & 60t are the legs and 300 is the hypotenuse\r \n" ); document.write( "\n" ); document.write( "(50t)^2+(60t)^2=300^2\r \n" ); document.write( "\n" ); document.write( "2500t^2+3600t^2= 90000\r \n" ); document.write( "\n" ); document.write( "6100t^2= 90000\r \n" ); document.write( "\n" ); document.write( "t^2= 90000/6100 \n" ); document.write( "=3.84 hours\r \n" ); document.write( "\n" ); document.write( "=3 50 minutes\r \n" ); document.write( "\n" ); document.write( "at 11.50 am they will be 300 km apart \n" ); document.write( " |