document.write( "Question 68406: 6x^3 = 18x + 60x^2\r
\n" ); document.write( "\n" ); document.write( "SOLVE \n" ); document.write( "
Algebra.Com's Answer #48709 by checkley71(8403)\"\" \"About 
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6X^3=18X+60X^2
\n" ); document.write( "6X^3-60X^2-18X=0
\n" ); document.write( "6X(X^2-10X-3)=0
\n" ); document.write( "USING THE QUADRATIC EQUATION WE GET
\n" ); document.write( "X=(-B+-SQRT[B^2-4*A*C])/2A
\n" ); document.write( "X=(10+-SQRT[100-4*1*-3])/2*1
\n" ); document.write( "X=(10+-SQRT100+12)/2
\n" ); document.write( "X=(10+-SQRT112)/2
\n" ); document.write( "X=(10+-10.583)/2
\n" ); document.write( "X=(10+10.583)/2
\n" ); document.write( "X=20.583/2
\n" ); document.write( "X=10.2915 ANSWER
\n" ); document.write( "X=(10-10.583)/2
\n" ); document.write( "X=-.2915 ANSWER\r
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