document.write( "Question 808520: Find all values of x in the interval [0, 2π] that satisfy the given equation.\r
\n" ); document.write( "\n" ); document.write( "-sin2x = (squreroot 2) cos x\r
\n" ); document.write( "\n" ); document.write( "How do I do this?
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Algebra.Com's Answer #487060 by DrBeeee(684)\"\" \"About 
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Given:
\n" ); document.write( "(1) \"-sin2x+=+sqrt%282%29%2Acosx\"
\n" ); document.write( "Use the trig identity for double-angle formulas
\n" ); document.write( "(2) \"sin2x+=+2sinx%2Acosx\" and get
\n" ); document.write( "(3) \"-2sinx%2Acosx+=+sqrt%282%29%2Acosx\"
\n" ); document.write( "Now as long as cos(x) is not equal to zero (to be verified) we can divide both sides of (3) by cos(x) and get
\n" ); document.write( "(4) \"sinx+=+-1%2Fsqrt%282%29\" or
\n" ); document.write( "(5) \"x+=+arcsin%28-1%2Fsqrt%282%29%29\" or
\n" ); document.write( "(6) x = 225 and 315 degrees.
\n" ); document.write( "Since neither angle has it's cosine equal to zero, the division by cosx in (3) was allowed.
\n" ); document.write( "Answer: x = {225,315} degrees.
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