document.write( "Question 808437: A person's average was 64%. One the next test he got 68%. This raised his average to 65%. The next test, his average improved by 1% again. What did he get on the last test?
\n" ); document.write( "I thought of doing trial and error: I tried adding everything and dividing by the amount plus the number of extra 64s, but it took too long. I still don't know what the answer is. Please help me!
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Algebra.Com's Answer #487006 by KMST(5328)\"\" \"About 
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We assume the 64% average was the average of \"n\" tests.
\n" ); document.write( "THe sum of the grades of those \"n\" tests was
\n" ); document.write( "\"64n\" .
\n" ); document.write( "When the next test grade was 68%, the sum of the grades of all the tests was
\n" ); document.write( "\"64n%2B68\" , and since there were \"n%2B1\" tests by then,
\n" ); document.write( "the average was \"%2864n%2B68%29%2F%28n%2B1%29\" .
\n" ); document.write( "We are told that average was 65%, so
\n" ); document.write( "\"%2864n%2B68%29%2F%28n%2B1%29=65\" --> \"64n%2B68=65%28n%2B1%29\" --> \"64n%2B68=65n%2B65\" --> \"68-65=65n-64n\" --> \"3=n\" .
\n" ); document.write( "So the average was 64% after 3 tests and 65% after 4 tests.
\n" ); document.write( "After the 5th test, the average was 1% higher (than 65%),
\n" ); document.write( "so it was 65% + 1% = 66%.
\n" ); document.write( "The sum of the first 4 tests was \"65%2A4=260\"
\n" ); document.write( "With a percentage score of \"x\" on the fifth test,
\n" ); document.write( "the sum of the grades on the first 5 tests is
\n" ); document.write( "\"260%2Bx\"
\n" ); document.write( "The average for the first 5 tests can be calculated as
\n" ); document.write( "\"%28260%2Bx%29%2F5\"
\n" ); document.write( "and since the average is 66%,
\n" ); document.write( "\"%28260%2Bx%29%2F5=66\" --> \"260%2Bx=66%2A5\" --> \"260%2Bx=330\" --> \"x=330-260\" --> \"highlight%28x=70%29\"
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