document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68460>Question 68460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am doing the best i can with algebra can you check my problem and let me know what is wrong?     <BR>\n" );
document.write( "7(3x+4)=8(2x+5)+13<BR>\n" );
document.write( "21x+28=8(2x+5)+13<BR>\n" );
document.write( "21x+28=16x+40+13<BR>\n" );
document.write( "-16x  -16x<BR>\n" );
document.write( "28-40+13<BR>\n" );
document.write( "28-53<BR>\n" );
document.write( "=25 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48699 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 7(3x+4) = 8(2x+5) + 13<BR>\n" );
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document.write( "21x + 28 = 8(2x+5) + 13<BR>\n" );
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document.write( "21x + 28 = 16x + 40 + 13<BR>\n" );
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document.write( "21x - 16x + 28 = 16x -16x + 53; subtracted 16x from both sides, added 40 & 13<BR>\n" );
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document.write( "5x + 28 = 53<BR>\n" );
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document.write( "Subtract 28 from both sides and you have;<BR>\n" );
document.write( "5x = 53 - 28<BR>\n" );
document.write( "5x = 25<BR>\n" );
document.write( "1x = 25/5; divided both sides by 5<BR>\n" );
document.write( "x = 5<BR>\n" );
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document.write( "Check the solution in original equation:<BR>\n" );
document.write( "7(3x+4) = 8(2x+5) + 13<BR>\n" );
document.write( "7[3(5) + 4] = 8[2(5)+ 5] + 13<BR>\n" );
document.write( "7(15 + 4) = 8(10 + 5) + 13<BR>\n" );
document.write( "7(19) = 8(15) + 13<BR>\n" );
document.write( "133 = 120 + 13 proves out solution<BR>\n" );
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