document.write( "Question 68453: The revenue for a sandwich shop is directly proportional to its advertising budget. When the owner spent $2000 a month on advertising, the revenue was $120,000. If the revenue is now $180,000, how much is the owner spending on advertising? \n" ); document.write( "

Algebra.Com's Answer #48694 by funmath(2933) $\"\"$ $\"About$

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The revenue for a sandwich shop is directly proportional to its advertising budget. When the owner spent $2000 a month on advertising, the revenue was $120,000. If the revenue is now $180,000, how much is the owner spending on advertising?
\n" ); document.write( "Let revenue be: R
\n" ); document.write( "Let advertising budget be: B
\n" ); document.write( "The constant of proportionality: k
\n" ); document.write( "Then R=kB
\n" ); document.write( "To find k, let B=2000 and R=120000 and solve for k.
\n" ); document.write( " $\"120000=k%282000%29\"$
\n" ); document.write( " $\"120000%2F2000=k%282000%29%2F2000\"$
\n" ); document.write( " $\"60=k\"$
\n" ); document.write( "Therefore, R=60B Is our forumal to answer the question.
\n" ); document.write( "Now let R=180000 and solve for B
\n" ); document.write( " $\"180000=60B\"$
\n" ); document.write( " $\"180000%2F60=60B%2F60\"$
\n" ); document.write( " $\"highlight%283000=B%29\"$
\n" ); document.write( "Therefore the owner spent $3000 on advertising.
\n" ); document.write( "Happy Calculating!!!! \n" ); document.write( "

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