document.write( "Question 808325: you need to use 3 calculations of drug H containing respectively 50%, 20% and 5% to make 600ml of 10% drug H. how much of the 50% will you use?\r
\n" ); document.write( "\n" ); document.write( "How much 30% alcohol, 45% alcohol. 60% alcohol and 95% alcohol could be mixed to make 200ml of 50% alcohol\r
\n" ); document.write( "\n" ); document.write( "These 2 questions how to solve for me
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Algebra.Com's Answer #486935 by Alan3354(69443)\"\" \"About 
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you need to use 3 calculations of drug H containing respectively 50%, 20% and 5% to make 600ml of 10% drug H. how much of the 50% will you use?
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\n" ); document.write( "You can make 10% using 50% and 5%.
\n" ); document.write( "Do it like this one. Only the numbers are different.
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\n" ); document.write( "Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use?
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\n" ); document.write( "e = amount of 8%
\n" ); document.write( "f = amount of 56%
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\n" ); document.write( "e+ f = 8 (total solution)
\n" ); document.write( "8e + 56f = 20*8 (total saline)
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\n" ); document.write( "e+ f = 8
\n" ); document.write( "e + 7f = 20
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\n" ); document.write( "-6f = -12
\n" ); document.write( "f = 2
\n" ); document.write( "e = 6
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\n" ); document.write( "How much 30% alcohol, 45% alcohol. 60% alcohol and 95% alcohol could be mixed to make 200ml of 50% alcohol
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\n" ); document.write( "To make 50%, you need to mix one higher and one lower concentration, eg, 30% & 60%, 30% & 95%, etc.
\n" ); document.write( "See above.
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\n" ); document.write( "PS Tutoring is not doing it for you.
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