document.write( "Question 808325: you need to use 3 calculations of drug H containing respectively 50%, 20% and 5% to make 600ml of 10% drug H. how much of the 50% will you use?\r
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document.write( "How much 30% alcohol, 45% alcohol. 60% alcohol and 95% alcohol could be mixed to make 200ml of 50% alcohol\r
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document.write( "These 2 questions how to solve for me \n" );
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Algebra.Com's Answer #486935 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! you need to use 3 calculations of drug H containing respectively 50%, 20% and 5% to make 600ml of 10% drug H. how much of the 50% will you use? \n" ); document.write( "------- \n" ); document.write( "You can make 10% using 50% and 5%. \n" ); document.write( "Do it like this one. Only the numbers are different. \n" ); document.write( "----------- \n" ); document.write( "Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use? \n" ); document.write( "================ \n" ); document.write( "e = amount of 8% \n" ); document.write( "f = amount of 56% \n" ); document.write( "--- \n" ); document.write( "e+ f = 8 (total solution) \n" ); document.write( "8e + 56f = 20*8 (total saline) \n" ); document.write( "--- \n" ); document.write( "e+ f = 8 \n" ); document.write( "e + 7f = 20 \n" ); document.write( "------------ Subtract \n" ); document.write( "-6f = -12 \n" ); document.write( "f = 2 \n" ); document.write( "e = 6 \n" ); document.write( "========================================== \n" ); document.write( "How much 30% alcohol, 45% alcohol. 60% alcohol and 95% alcohol could be mixed to make 200ml of 50% alcohol \n" ); document.write( "-- \n" ); document.write( "To make 50%, you need to mix one higher and one lower concentration, eg, 30% & 60%, 30% & 95%, etc. \n" ); document.write( "See above. \n" ); document.write( "---------------- \n" ); document.write( "PS Tutoring is not doing it for you. \n" ); document.write( " \n" ); document.write( " |