document.write( "Question 808307: How much 30% alcohol, 45% alcohol, 60% alcohol and 95% alcohol could be mixed to make 200ml of 50% alcohol.\r
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document.write( "Who solve it for me \n" );
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Algebra.Com's Answer #486923 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How much 30% alcohol, 45% alcohol, 60% alcohol and 95% alcohol could be mixed to make 200ml of 50% alcohol. \n" ); document.write( "------- \n" ); document.write( "Equations: \n" ); document.write( "Quantity:: t + f + s + n = 200 mL \n" ); document.write( "Alcohol::: 0.3t+0.45s+0.95n = 0.50*200 \n" ); document.write( "================== \n" ); document.write( "You have 4 variables. \n" ); document.write( "You need two more equation statements to solve. \n" ); document.write( "======================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |