document.write( "Question 808302: You need to use 3 solutions of drug H containing respectively 50%, 20% & 5% to make 600ml of 10% drug H. How much of the 50% will you use?\r
\n" ); document.write( "\n" ); document.write( "My own calculation 50% = 55ml
\n" ); document.write( " 20% = 109ml
\n" ); document.write( " 5% = 437ml\r
\n" ); document.write( "\n" ); document.write( "who helps me to solve it for me step by step
\n" ); document.write( "

Algebra.Com's Answer #486916 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
You can use 50% and 5%, or 20% and 5%.
\n" ); document.write( "There's no reason to use all 3.
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\n" ); document.write( "Do it like this one. Only the numbers are different.
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\n" ); document.write( "Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use?
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\n" ); document.write( "e = amount of 8%
\n" ); document.write( "f = amount of 56%
\n" ); document.write( "---
\n" ); document.write( "e+ f = 8 (total solution)
\n" ); document.write( "8e + 56f = 20*8 (total saline)
\n" ); document.write( "---
\n" ); document.write( "e+ f = 8
\n" ); document.write( "e + 7f = 20
\n" ); document.write( "------------ Subtract
\n" ); document.write( "-6f = -12
\n" ); document.write( "f = 2
\n" ); document.write( "e = 6
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