document.write( "Question 808302: You need to use 3 solutions of drug H containing respectively 50%, 20% & 5% to make 600ml of 10% drug H. How much of the 50% will you use?\r
\n" );
document.write( "\n" );
document.write( "My own calculation 50% = 55ml
\n" );
document.write( " 20% = 109ml
\n" );
document.write( " 5% = 437ml\r
\n" );
document.write( "\n" );
document.write( "who helps me to solve it for me step by step \n" );
document.write( "
Algebra.Com's Answer #486916 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! You can use 50% and 5%, or 20% and 5%. \n" ); document.write( "There's no reason to use all 3. \n" ); document.write( "====================== \n" ); document.write( "Do it like this one. Only the numbers are different. \n" ); document.write( "----------- \n" ); document.write( "Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use? \n" ); document.write( "================ \n" ); document.write( "e = amount of 8% \n" ); document.write( "f = amount of 56% \n" ); document.write( "--- \n" ); document.write( "e+ f = 8 (total solution) \n" ); document.write( "8e + 56f = 20*8 (total saline) \n" ); document.write( "--- \n" ); document.write( "e+ f = 8 \n" ); document.write( "e + 7f = 20 \n" ); document.write( "------------ Subtract \n" ); document.write( "-6f = -12 \n" ); document.write( "f = 2 \n" ); document.write( "e = 6 \n" ); document.write( " |