document.write( "Question 68353: can you please show me how to work this out?
\n" ); document.write( "Patrick drove 3 h to attend a meeting. On the return trip,
\n" ); document.write( "his speed was 10 mi/h less and the trip took 4 h. What was his speed each way? \n" ); document.write( "
Algebra.Com's Answer #48691 by ankor@dixie-net.com(22740)\"\" \"About 
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can you please show me how to work this out?
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\n" ); document.write( "Patrick drove 3 h to attend a meeting. On the return trip,
\n" ); document.write( "his speed was 10 mi/h less and the trip took 4 h. What was his speed each way?
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\n" ); document.write( "We don't know the distance, but we know the distance at the two different speeds is equal.
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\n" ); document.write( "Let s = speed to the meeting
\n" ); document.write( "Then (s-10) = speed back
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\n" ); document.write( "Dist = time * speed:
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\n" ); document.write( "Dist in 3 hrs = Dist in 4 hr
\n" ); document.write( "3s = 4(s-10)
\n" ); document.write( "3s = 4s - 40
\n" ); document.write( "3s - 4s = -40
\n" ); document.write( "-1s = -40
\n" ); document.write( "s = +40 mph to the meeting
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\n" ); document.write( "40 - 10 = 30 mph on the return trip
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\n" ); document.write( "Check our solution: 3 * 40 = 4 * 30
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\n" ); document.write( "Do you know how to do this now?
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