document.write( "Question 68415: A long-distance phone call costs $0.96 for the first minute and $0.72 for each additional minute or portion thereof. Write an inequality reprssenting the number of minutes a person could talk without exceeding $6. \n" ); document.write( "
Algebra.Com's Answer #48689 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! x=number of minutes a person can talk without exceeding $6.00\r \n" ); document.write( "\n" ); document.write( "$0.72(x-1)+$0.96 =cost for x minutes and that has to be less than or equal to $6.00. So, our inequality is:\r \n" ); document.write( "\n" ); document.write( "$0.72(x-1)+$0.96=<$6.00 clear parens\r \n" ); document.write( "\n" ); document.write( "$0.72x-$0.72+$0.96=<$6.00\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "$0.72x+$0.24=<$6.00 subtract $0.24 from both sides\r \n" ); document.write( "\n" ); document.write( "$0.72x=<$6.00-$0.24\r \n" ); document.write( "\n" ); document.write( "$0.72x=<$5.76 divide both sides by $0.72\r \n" ); document.write( "\n" ); document.write( "x=<8 minutes-----------------------------answer\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ck\r \n" ); document.write( "\n" ); document.write( "8 minutes costs $0.96 + 7($0.72)= \n" ); document.write( "8 minutes cost $0.96+$5.04=$6.00\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |