document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68427>Question 68427</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131467735/algebrahomeworkh>Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> On a recent trip to Florida, we averaged 50 miles per hour.  On the return trip we averaged 60 miles per hour.  What do you think the average speed of the trip to Florida and back was? Defend your position. Algebraically, determine the average speed of the trip to Florida and back. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48688 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48688\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Distance(d)=rate(r) times time(t) or d=rt and t=d/r\r<BR>\n" );
document.write( "\n" );
document.write( "Time down=d/50<BR>\n" );
document.write( "Time back=d/60\r<BR>\n" );
document.write( "\n" );
document.write( "Average Speed equals total distance divided by total time\r<BR>\n" );
document.write( "\n" );
document.write( "Total distance=2d\r<BR>\n" );
document.write( "\n" );
document.write( "Total time=d/50+d/60 so\r<BR>\n" );
document.write( "\n" );
document.write( "Average Speed=2d/(d/50+d/60)  \r<BR>\n" );
document.write( "\n" );
document.write( "DENOMINATOR: LCM is 300: (d/50+d/60)=(6d+5d)/300=11d/300 now we have\r<BR>\n" );
document.write( "\n" );
document.write( "Average Speed=2d/(d/50+d/60) =2d/(11d/300)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Average Speed=2d(300/11d)=600/11=54.545 mph---------------------answer  \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Defense: average speed is defined as total distance divided by total time and that's what we have calculated\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps----ptaylor<BR>\n" );
document.write( " <BR>\n" );
document.write( "  \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );