document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=808213>Question 808213</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man is now 3 times as old as his son.in 10 years time the sum of their ages will be 76. how old was the man, when his son was born?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486875 by </B><A HREF=/tutors/aboutme.mpl?userid=JBarnum><B>JBarnum(2146)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JBarnum><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JBarnum><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486875\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is an age question and you could easily find out how to solve this by reviewing any of the thousands of age questions on this site...they all work the same way\r<BR>\n" );
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document.write( "m=3s<BR>\n" );
document.write( "m+10+s+10=76<BR>\n" );
document.write( "m+s=56<BR>\n" );
document.write( "3s+s=56<BR>\n" );
document.write( "4s=56<BR>\n" );
document.write( "s=14<BR>\n" );
document.write( "m=3s<BR>\n" );
document.write( "m=3(14)<BR>\n" );
document.write( "m=42 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );