document.write( "Question 808203: Any number divided by what number will give the last digit as the remainder and the rest of the digit as the quotient. \n" ); document.write( "
Algebra.Com's Answer #486872 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
so your saying:
\n" ); document.write( "100/n=x and the last digit of x will be the remainder of said number
\n" ); document.write( ",, if n=10
\n" ); document.write( "100/n=x
\n" ); document.write( "x=10 with 0 being remainder that works
\n" ); document.write( ",,
\n" ); document.write( "1/n=y
\n" ); document.write( "y=.1 with 1 bing the last digit that doesnt work
\n" ); document.write( ",,
\n" ); document.write( "-1/n=z
\n" ); document.write( "z=-.1 which has same issue that doesnt work
\n" ); document.write( ",,
\n" ); document.write( "25/n=q
\n" ); document.write( "q=2.5 where 5 is the remainder for which this works
\n" ); document.write( ",,
\n" ); document.write( "2/n=r
\n" ); document.write( "r=.2 where 2 is the remainder of nothing doesnt work
\n" ); document.write( ",, this seems to work for all numbers greater than or equal to 10 or lesthan or equal to -10 if n=10
\n" ); document.write( "but there are too many numbers to keep guessing n checking good luck theres just not enough information to solve \n" ); document.write( "
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