document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=808195>Question 808195</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 72 persons have enough food for 7 days but after one day they decided to finish the food in 3 remaining days. For it they invited more persons. how many persons did they invite? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486838 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486838\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 72*7=504 person days of food<BR>\n" );
document.write( "after one they have used 72 person days<BR>\n" );
document.write( "504-72=432 person days remaining after one day<BR>\n" );
document.write( "432/(72+x)=3<BR>\n" );
document.write( "x=72 more invited<BR>\n" );
document.write( "which makes sense since now they have 6 days for 72<BR>\n" );
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