document.write( "Question 68426: -x+y=1
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document.write( "2x+y=-2 \n" );
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Algebra.Com's Answer #48679 by rmromero(383)![]() ![]() ![]() You can put this solution on YOUR website! -x+y=1 \n" ); document.write( "2x+y=-2\r \n" ); document.write( "\n" ); document.write( "Here are the Steps Systems of Equation using Substition method \n" ); document.write( "1. In either equation, solve for one variable in terms of the other. \n" ); document.write( " --> -x + y = 1 \n" ); document.write( " x = y - 1 \n" ); document.write( " \n" ); document.write( "2. Substitute y - 1 for for x in the other equation 2x + y = -2. Solve. \n" ); document.write( " --> 2(y-1) + y = -2 \n" ); document.write( " 2y - 2 + y = -2 \n" ); document.write( " 3y = 0 \n" ); document.write( " y = 0 \n" ); document.write( " \n" ); document.write( "3. Substitute the result from step 2 in either equation. Solve for the other variable. \n" ); document.write( " --> -x + y = 1, y =0 \n" ); document.write( " -x + 0 = 1 \n" ); document.write( " -x = 1 \n" ); document.write( " x = -1 \n" ); document.write( " \n" ); document.write( "4. Check the solution in both original equations. \n" ); document.write( "A. -x + y = 1, y=0 , x=-1 \n" ); document.write( " -(-1) + 0 = 1 \n" ); document.write( " 1 = 1 ------------------->> true \n" ); document.write( " \n" ); document.write( "B. 2x + y = -2, y =0, x = -1 \n" ); document.write( " 2(-1) + 0 = -2 \n" ); document.write( " -2 = -2 ------------------>> True\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Therefore the solution of the system of the equation is (-1, 0) \n" ); document.write( " |