document.write( "Question 808111: The dean of students of a large community
\n" ); document.write( "college claims that the average distance that
\n" ); document.write( "commuting students travel to the campus is 32
\n" ); document.write( "miles. The commuting students feel otherwise.
\n" ); document.write( "A sample of 64 students was randomly selected
\n" ); document.write( "and yielded a mean of 35 miles and a standard
\n" ); document.write( "deviation of 5 miles. Find and interpret the 90%
\n" ); document.write( "confidence interval for the average distance that
\n" ); document.write( "commuting students travel to the campus.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #486745 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The commuting students feel otherwise.
\n" ); document.write( "A sample of 64 students was randomly selected
\n" ); document.write( "and yielded a mean of 35 miles and a standard
\n" ); document.write( "deviation of 5 miles. Find and interpret the 90%
\n" ); document.write( "confidence interval for the average distance that
\n" ); document.write( "commuting students travel to the campus.
\n" ); document.write( "-----
\n" ); document.write( "sample mean = x-bar = 35 miles
\n" ); document.write( "-----
\n" ); document.write( "ME = 1.645*5/sqrt(64) = 1.028
\n" ); document.write( "-----
\n" ); document.write( "95% CI: 35-1.028 < u < 35+1.028
\n" ); document.write( "95% CI: 33.9720 < u < 36.028
\n" ); document.write( "=======
\n" ); document.write( "We can be 95% certain that the average travel distance is
\n" ); document.write( "between 33.97 and 36.03
\n" ); document.write( "
\n" );