document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=808077>Question 808077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 times the width. The area is 48 square feet. Find the length and width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486709 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486709\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = width<BR>\n" );
document.write( "3x = length   {length is 3 times the width}\r<BR>\n" );
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document.write( "Area of a rectangle = length x width\r<BR>\n" );
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document.write( "x(3x) = 48   {substituted length and width into area formula}<BR>\n" );
document.write( "3x² = 48   {multiplied}<BR>\n" );
document.write( "x² = 16   {divided each side by 3}<BR>\n" );
document.write( "x = 4 or -4   {took square root of each side}\r<BR>\n" );
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document.write( "x = 4   {width cannot be negative}<BR>\n" );
document.write( "3x = 12   {substituted 4, in for x, into 3x}\r<BR>\n" );
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document.write( "width = 4 ft<BR>\n" );
document.write( "length = 12 ft<BR>\n" );
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