document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=808036>Question 808036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2log(x-1) = 2 + log100\r<BR>\n" );
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document.write( "Can you please help me? Thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486698 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2log(x-1) = 2 + log100<BR>\n" );
document.write( "note that log 100 = log (base 10) 100 and 10^2 = 100 so log 100 = 2<BR>\n" );
document.write( "2log(x-1) = 2 + 2<BR>\n" );
document.write( "2log(x-1) = 4<BR>\n" );
document.write( "divide both sides of = by 2<BR>\n" );
document.write( "log(x-1) = 2<BR>\n" );
document.write( "note that log base is 10 and by definition of logarithm<BR>\n" );
document.write( "x-1 = 10^2<BR>\n" );
document.write( "x = 100 +1<BR>\n" );
document.write( "x = 101<BR>\n" );
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