document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=807981>Question 807981</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ladder 2x+1 feet is positioned against a wall such that the bottom is x-1 feet away from a wall. The distance between the floor and the top of the ladder is 2x feet. <BR>\n" );
document.write( "Find the length, in feet of the ladder;<BR>\n" );
document.write( "Assume that a right angle is formed by the wall and the floor;<BR>\n" );
document.write( "The length of the ladder is --------- feet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486696 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2x+1) is the length of ladder which is the hypotenuse\r<BR>\n" );
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document.write( "2x is one leg<BR>\n" );
document.write( "and x-1 is the other leg\r<BR>\n" );
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document.write( "(2x)^2+(x-1)^2= (2x+1)^2  \r<BR>\n" );
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document.write( "4x^2+x^2-2x+1=4x^2+4x+1\r<BR>\n" );
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document.write( "x^2-6x=0<BR>\n" );
document.write( "x^2=6x\r<BR>\n" );
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document.write( "x=6 Or x=0<BR>\n" );
document.write( "x cannot be 0\r<BR>\n" );
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document.write( "5,12,13 </SPAN>\n" );
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